Tech for good

Example 1:gifts = [25, 64, 9, 4, 100], k = 4[25, 64, 9, 4, 100]-> (1회) [25, 64, 9, 4, 10]-> (2회) [25, 8, 9, 4, 10]-> (3회) [5, 8, 9, 4, 10]-> (4회) [5, 8, 9, 4, 3] (floor or the square root - floor: 내림)5 + 8 + 9 + 4 + 3 = 29 Follow these steps:Pick the largest pile of gifts.Replace it with the floor of its square root.Repeat this for k seconds.🔧 Best Tool for This?We need to efficiently get the l..

class Solution: def maxProduct(self, nums: List[int]) -> int: # Convert to max-heap by pushing negative values max_heap = [-num for num in nums] heapq.heapify(max_heap) # Pop the two largest values first_max = -heapq.heappop(max_heap) second_max = -heapq.heappop(max_heap) return (first_max - 1) * (second_max - 1)